refactor(sort): replace lexicalSort with naturalSort for better string comparison

Use localeCompare with numeric sensitivity for more natural string sorting behavior

scripts/sort.ts

@@ -18,17 +18,29 @@ function lexicalSort(a: string, b: string): number {
 }
 
 /**
- * 对对象的键按照字典序进行排序（支持嵌套对象）
- * @param obj 需要排序的对象
- * @returns 返回排序后的新对象
+ * Natural sort function for strings, meant to be used as the sort
+ * function for `Array.prototype.sort`.
+ *
+ * @param a - First element to compare.
+ * @param b - Second element to compare.
+ * @returns A number indicating which element should come first.
+ */
+function naturalSort(a: string, b: string): number {
+  return a.localeCompare(b, undefined, { numeric: true, sensitivity: 'base' })
+}
+
+/**
+ * Sort object keys in dictionary order (supports nested objects)
+ * @param obj The object to be sorted
+ * @returns A new object with sorted keys
  */
 export function sortedObjectByKeys(obj: object): object {
-  const sortedKeys = Object.keys(obj).sort(lexicalSort)
+  const sortedKeys = Object.keys(obj).sort(naturalSort)
 
   const sortedObj = {}
   for (const key of sortedKeys) {
     let value = obj[key]
-    // 如果值是对象，递归排序
+    // If the value is an object, sort it recursively
     if (typeof value === 'object' && value !== null && !Array.isArray(value)) {
       value = sortedObjectByKeys(value)
     }